Hello brilliants can you solve these questions about vectors ?
1.3 If A = 4ax - 2ay + 6az and B = 12ax + 18ay - 8az, determine:
(a) A - 3B
(b) (2A + 5B) / |B|
(c) ax X A
(d) (B X ax) · ay
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6(ax + by) = 3a + 2b
6ax + 6by = 3a + 2b --------- (1)
6(bx - ay) = 3b - 2a
6bx - 6ay = 3b - 2a ------------- (2)
On solving (1) * a & (2) * b, we get
6ax^2 + 6aby = 3a^2 + 2ab
6b^2x - 6aby = 3b^2 - 2ab
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6ax^2 + 6b^2x = 3a^2 + 3b^2
6x(a^2 + b^2) = 3(a^2 + b^2)
x = 3/6
x = 1/2.
Substitute x = 1/2 in above equations, we get
6ax + 6by = 3a + 2b
6a(1/2) + 6by = 3a + 2b
3a + 6by = 3a + 2b
6by = 2b
y = 2b/6b
y = 1/3.
Therefore the value of x = 1/2 and y = 1/3.
Hope this helps!
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Any book please ask this??
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thx
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