Question

hello buddies can u help me out.......​

Answer 1

Step-by-step explanation:

Solution is given in above pic ...

Mark it Brainliest answer

Answer 2

Answer:

$\huge\underline\bold\red{Answer!!}$

$we \: know \: that$

curved surface area of frustum=

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi(r1 + r2)l$

$here \: l = 4cm$

$we \: need \: to \: find \: r1 \: and \: r2$

FOR r1 :-

$circumference \: of \: 1st \: end= \: 18cm$

$2\pi \: r1 = 18$

$r1 = \frac{18}{ 2} \times \frac{1}{\pi}$

$r1 = \frac{9}{\pi}$

FOR r2 :-

$circumference \: of \: 2nd \: end = 6cm$

$2\pi \: r2 = 6$

$r2 = \frac{6}{2} \times \frac{1}{\pi}$

$r2 = \frac{3}{\pi}$

Now,

Curved surface area of frustum =

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \: \pi(r1 + r2)l$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi( \frac{9}{\pi} + \frac{3}{\pi} ) \times 4$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi( \frac{9 + 3}{\pi} ) \times 4$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times \frac{12}{\pi} \times 4$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 48cm {}^{2}$

Hence, curved surface area of frustum = 48cm²

Hope it helps you..............❤️❤️