Question

hello~♥~(~_^)



calculate the angle of derivation for the thin prism of Glass n is equal to 1.5 and having refracting angle 8 degree.​

Answer 1

Explanation:

(D_m)= 2r= A

So, (D_m)= 2(i-r) (You already know)

Now, 2r= 2(i-r)

Finally, i= 2r

Now, the refractive index given in the question is 1.5

So, {sin (i)}/{sin (r)}= 1.5

Now putting the value of i as 2r in the above equation, we get-

{sin (2r)}/{sin (r)}= 1.5

On using the “Sine Addition formula”,

2{cos (r)}= 1.5

So, {cos (r)}= 0.75

Answer 2

answer:

A similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index

similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index=>sin{(60+Dm)/2}/sin30°=1.5

similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index=>sin{(60+Dm)/2}/sin30°=1.5=>sin{30+(Dm/2)}=1.5×(1/2)=0.75

similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index=>sin{(60+Dm)/2}/sin30°=1.5=>sin{30+(Dm/2)}=1.5×(1/2)=0.75=>30°+(Dm/2)=sin-1(0.75)=47.73°

similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index=>sin{(60+Dm)/2}/sin30°=1.5=>sin{30+(Dm/2)}=1.5×(1/2)=0.75=>30°+(Dm/2)=sin-1(0.75)=47.73°=>(Dm/2)=47.73–30=17.73°

similar problem being solved before using formulae [sin{(A+Dm)/2}]/sinA/2=refractive index=>sin{(60+Dm)/2}/sin30°=1.5=>sin{30+(Dm/2)}=1.5×(1/2)=0.75=>30°+(Dm/2)=sin-1(0.75)=47.73°=>(Dm/2)=47.73–30=17.73°=>Dm=17.73×2=35.46°

hope it helps..

thanku☺

#divu.