Question

Hello
Can any one help me with this
O.3 bar + 0.4 bar =?
Please help

Answer 1

Answer:

Let

i ) x = 0.3 bar

x = 0.3333.....----( 1 )

Multiply ( 1 ) with 10

10x = 3.3333..........( 2 )

Subtract ( 1 ) from ( 2 ) we get

9x = 3

x = 3/ 9 ----( 3 )

ii ) let y = 0.4 bar

y = 0.44444.......( 4 )

Multiply ( 4 ) with 10

10y = 4.4444......( 5 )

Subtract ( 4 ) from ( 5 ) we get

9y = 4

y = 4/ 9 ----------( 6 )

According to the problem ,

0.3 bar + 0.4 bar

= 3/ 9 + 4/ 9

= ( 3 + 4 )/9

= 7/ 9

Therefore ,

Required sum is 7 /9

I hope this helps you.

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