Question

Hello,Can u help me please:) ASAP just if u want to answer my math:) i hope u can help me, advance thank u:)

Answer 1

Answer:

1. 12^4

2. 8x^6

3. -1x

4. 3^3

5. I don't know

6. 30y

7. 3a

8. 3p^2

9. 20n

10. 1x

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Answer 2

Answer:

Step-by-step explanation:

ANSWER:-

Answering according to Attachments provided.

In attachment 1,

1. $\sf{3 \times 4^3}$

So, we know that 4^3 is actually 4*4*4 = 64

So, indirectly it is 3*64 = 192 is the first answer.

2. Next is $\sf{4x^3+2x^3}$

4 and 2 will get multiplied, and exponents will get added.

$\sf{(4 \times 2) ^{(3+3)}}$

3. Anything to the power 0 is 1. So the answer is 1.

4. The question is done in the attachment.

Multiplying Polynomials Attachment:-

6y(2y+3)

$\sf{ \mapsto 12y^2 + 18y}$

(2a-1)(8a-5)

= $\sf{16a^2 - 10a - 8a + 5}$

(4p-1)^2

So, we apply an identity for this!

$\sf{(a-b)^2 = a^2 + b^2 - 2ab}$

$\sf{(4p - 1)^2 = (4p)^2 + (1)^2 - 2(4p \times 1)}$

$\sf{ \implies 16p^2 + 1 - 8p}$

(2n+2)(6n+1)

$\sf{12n^2 + 2n + 12n + 2}$

$\sf{ \longrightarrow 12n^2 + 14n + 2}$

(7x-6)(5x+6)

$\sf{35x^2 + 42x - 30x -12}$

$\sf{35x^2 + 12x -12}$

Dividing the Polynomials Attachment:-

This is to be done in detail, so let's see!

1. $\sf{ - \dfrac{9a^3b^2}{3ab}}$

9 and 3 cancelld, ab cancelled with numerator and the answer is -3a^2b.

2. Taking 9 and r common from the numerator,

we can get the numerator as 9r(2r^4+4r^3+3r^2)

Now, we can cancel off 9r, and the required answer is :-

$\sf{2r^4+4r^3+3r^2}$

3. Done in the attachment, kindly refer to it.

4th one, the coefficients are reduced to 15x^3+ x^2+15x/5r^2 and no change in the alphabet portion, surely r and x can never be canclled.

5. we can not perform this operation as their is no common factor between the both operation.