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A compound 24×10^23 atoms of manganese and 48×10^23 atoms of oxygen are present. Find out the molecular formula.
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It's very easy..
From the question we can identify that the no.of oxygen atoms is twice as that of Manganese atoms...
So the molecular(as well as emperical) formula is MnO2
From the question we can identify that the no.of oxygen atoms is twice as that of Manganese atoms...
So the molecular(as well as emperical) formula is MnO2
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UmeshNaik:
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