Question

Hello dear brainly mathematicians........

Pls answer this question:

A box contains 100 cards marked with numbers 1 to 100. If one card is drawn from the box find the probability that it bears a number divisible by 8..

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Answer 1

☆Hola User_______________

☆Here is Your Answer...!!!

_______________________

☆Concept of Probability

☆Now we actually know that ...

☆The probability of any event is given as

☆P (E) = No.of favourable outcomes / total number of outcomes of the event

☆Now simply we know here that

☆Total number of outcomes are = 100 outcomes

☆And the condition is give that , the draw card should be a number divisible of 8 ...

☆so we know the number divsible by 8 within hundered are 12 numbers

☆thus probability will be

■P (E) = 12 / 100 = 6/50 = 3/25

☆Thus the probabality of the event will be

■P (E) = 3/25

〽P (E) = 0.12
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Answer 2

Answer:

$\huge\boxed{\bf{\green{\frac{3}{25}}}}$

$\mathtt{Probability=\frac{Total\:number\:of\:possibilities}{Total\:number\:of\:favourable\:outcomes}}$

Number of outcomes possible

There are 100 possible outcomes :-

{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99 , 100 }

Number of favourable outcomes :-

There are 12 favourable outcomes :

{ 8 , 16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96 }

Hence probability :-

$\frac{12}{100}\\\\\implies \frac{3}{25}\\\\or \:0.12$

Step-by-step explanation:

Numbers divisible by 10 starts from 8 .

8 , 16 ..... 96 .

No of terms can be easily calculated by the formula of n th term of an A.P .

a + ( n - 1 ) d = 96

⇒ 8 + ( n - 1 ) d = 96

⇒ 8( n - 1 ) = 88

⇒ n - 1 = 88/8

⇒ n - 1 = 11

⇒ n = 12