Question

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Answer my questions which are given in the attachment

❤Conditions=> Fullexplanation❤

Class => 11

Subject => Physics

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Jai bajarang bali

@Dr. S.M.

Answer 1

Frst one⬇️⬇️⬇️  ●●●Velocity of fuel leaving= 60km/s=60000m/s  ☆Mass of fuel burning per sec= 1kg  ●●Therefore F=ma  ☆=F= 1kg x 60000-0/1  ●●= F= 60000N  ☆☆This is the force exerted by the fuel on the rocket     Second⬇️⬇️⬇️ mass of rocket = 5000 kg, speed = 800 m/s , a = 20 m/s2, g = 10 m/s 2∆m/t=?according to newton's second law   a=v(∆m/t)÷m−g  >>20+10=800(∆m/t)/5000  >>30=8÷50× (∆m/t)(∆m/t)=50×30÷8=1500÷8=187.5kgs^−1  @skb