Question

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Answer 1

We note that the top green triangle has an area of the rectangle $\frac{1}{4}$ or $\frac{1}{4}$ × 160 = 40 as labelled. Let the area of the four white triangles be a, b, c and d as shown.

ATQ,

a + b + 12 + 40 = $\frac{160}{2}$ (i) Half the area of the rectangle.


c + d + 12 = $\frac{160}{4}$ (ii) Quarter the area of the rectangle.


(i) + (ii) : a + b + c + d = 56

= A white the area of white region. 


$\therefore{}$ A green region

=> A green = A rectangle - A white - A red

=> 160 - 56 - 12 = 92


$\boxed{92 \: is \: the \: answer}$

Answer 2

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