Question

hello everybody its my question is of maths so I requested to all the viewers and answerers please give me the right answer and who dont know so they dont give please...................... so question no. is first both parts

Answer 1

Question 1: Find the area of the triangle whose vertices are:

(2, 3), (-1, 0), (2, 4)
(-5, -1), (3, -5), (5, 2)
Solution: (a) We have; x1 = 2, y1 = 3, x2 = -1, y2 = 0, x3 =2, y3 = 4

Area of triangle can be calculated as follows:

= ½ [x1(y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)]

=1/2 [2(0 + 4) + (-1)(- 4 – 3) + 2(3 – 0)]

= ½ (8 + 7 + 6)

= ½ x 21 = 21/2 sq unit

Solution: (b) We have; x1 = -5, y1 = -1, x2 = 3, y2 = -5, x3 = 5, y3 = 2

Area of triangle can be calculated as follow:

= ½ [x1(y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)]

= ½ [ - 5(-5 – 2) + 3(2 + 1) + 5(-1 +5)]

= ½ (35 + 9 + 20)

= ½ x 64 = 32 sq unit