Question

Hello Everyone

Answer the question below:

$v = at + \frac{ alpha}{bitta}$
The velocity V of a particle depends on time t V = at +
the dimensions of alpha, bitta
and gama will be respectively
​

Answer 1

Since the unit of velocity is meter per second its dimensions are

[LT

−1

]

In order to equate the given equation the dimensions on either sides should be equal to [LT

−1

]

Given equation in dimensional form is

[LT

−1

]=α[T

1

]+β[T

−1

]+y

To obtain required dimensions we write equation as

[LT

−1

]=[LT

−2

][T

1

]+[L][T

−1

]+[LT

−1

]

Comparing both equations we get

α=[LT

−2

],β=[L],y=[LT

−1

]