Physics, asked by simra4825, 6 days ago

Hello everyone can anybody explain this answer properly

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Answered by Dioretsa
0

Distance of Jupiter from Earth

 \sf{\bold{D=824.7×10^6 ~km}}

Angular diameter

 \sf{\bold{35.72" = 35.72 × 4.874 × 10^{-6} ~rad}}

Diameter of Jupiter = d

using the relation ,

 \sf{\bold{θ = d/D }}

 \sf{\bold{d= θ }}

 \sf{\bold{D = 824.7×10^9 × 35.72 × 4.872 × 10^{-6} }}

 \sf{\bold{ = 143520.76× 10³ }}

 \sf{\bold{= 1.435 × 10⁵ km}}

Answered by boogrizzy17
2

Answer:

they are taking distance to that of radius and calculating

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