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For what value of p,6 is a zero of the polynomial
x^2 −(2p+1)x+6
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Value pf p = 3 if 6 is a zero of x² - (2p + 1)x + 6
Step-by-step explanation:
x² - (2p + 1)x + 6
6 is a zero
f(x) = x² - (2p + 1)x + 6
as 6 is a zero
=> f(6) = 0
=> 6² - (2p +1)*6 + 6 = 0
=> 36 - (2p +1)*6 + 6 = 0
=> 42 - (2p +1)*6 = 0
=> 7 - (2p +1) = 0
=> 2p +1 = 7
=> 2p = 6
=> p = 3
Hence Value pf p = 3 if 6 is a zero of x² - (2p + 1)x + 6
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