Question

Hello everyone
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For what value of p,6 is a
zero of the polynomial
x^2-(2p+1)x+6

solve with step by step explanation​

Answer 1

Step-by-step explanation:

We have to find the value of p

so.. it is given that 6 is a zero of the polynomial

so...

p(x) = x² - (2p+1)x+6

p(6) = 6² -(2p+1) 6 +6

0 = 36 - 12p - 6 +6

0 = 36 - 12p

-36 = -12p

-36/-12 = p

3 =p...

$\bigstar$so... the value of p is 3 .. if p = 3 then 6 is the zero of the polynomial..

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