Math, asked by raomalikneha1, 1 year ago

hello everyone good morning my question is

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Answered by vaishnavivishwa
1
PQ= √( 10 - 2)^2 + ( y -(-3))^2 =10
=> (8)^2 + (y + 3)^2 = (10)^2
==> 64 + y^2 + 9 + 6y = 100
=> 73+ y^2 +6y = 100
=> y^2 +6y = 27
y^2 + 9y - 3y - 27 =0
y ( y+ 9) - 3 (y+9) =0
(y-3) (y+9)
y = 3, -9
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