Question

HELLO EVERYONE.

here any genius who can answer this...

The Cubic polynomial f(x) is such

that the coefficient of x³ is -1 and

the zeroes of f(x) are 1,2 and K. if

f(x) has a remainder of 8 when

divided by x-3, then find

the value of k

Answer 1

Hey value of k is 7.
Just use properties of sum , product and product of zeros taken two at a time and then use division theorem and you will get the answer

Answer 2

Answer: since 1,2 and K are the zeros of FX and coefficient of x cube is -1 so x minus one, x minus 2, and minus x + k are the factors of FX

So, f x is equals to (3 - 1 ) (3 - 2)(-3+k)=8

= 2(-3+k) = 8

= -3+k = 4

= k = 7

Hope it helps you

Step-by-step explanation: