Question

hello everyone. needed help here.....

Answer 1

Hey .......mate .
here is your answer

As per given data
R1=5ohm
R2=10ohm
R3=30ohms
As these are in parallel connection the effective resistance= 1/R effective =1/R1+1/R2+1/R3= 1/5+1/10+1/30 =1/3
So R effective = 3ohms
...So total current resistance = 3ohms

Current through each resistance .......
----------------------------
Since these are in parallel Voltage become constant
So let current flowing through resistance R1=i1
current in R2=i2
Current in R3=i3

so current i=i1+i2+i3
since we know i=v/r==12/3=4 A
So i1=v/R1
i2=v/R2
i3= v/R3

v/R= v/R1+v/R2+v/R3
i=v(1/R1+1/R2+1/R3 )
v= (R1R2R3)i /R2R3+R1R3+R1R2


So i1= v/R1 ==> (R2R3)i/ R2R3+R1R3+R1R2
===> 10× 30×4/ 500= 12/5=2.4 A
similarly i2= v/R2==> R1R3i/R2R3+R1R3+R1R2
, ==> 150×4/500=12/10=1.2A
I3= 1×4×50/500=4/10=0.4A



So total current in circuit is 4A
current through each resistance is 2.4,1.2,0.4.Amperes
Total current resistance is 3ohms



Hope you got your answer