Question

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✴ questions

❄❄program to add two matrices?

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Answer 1

answer :

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first remember that sum and different operations are possible on two identical matrices.for instance , A [n] [m] and B [p] [Q] are the two given matrices , then, in order to program sum and difference operations following must be true :


n = p and m = q

the program to add two matrices is as follows :

#include <iostream.h>

#include <process .h > // for exist ( ) function

int main ( )

{

int a [ 10 ] [ 10 ] , b [ 10 ] [10] , c [ 10 ] [10] ;

int i , j , m, n, p , q ;



// Input rows & columns of matrices A [ m]

[n] and B [ p ] [ q] .

cout << " \ n Input row & column of matrix - A \ n " ;

cin >> m >> n;

cout <<" \ nInput row & column of matrix - B \n " ;

cin >> p >> q;

if (( m = = p ) & & ( n = = q) ) // check if matrix can be added .

cout <<" matrix can be added \ n" ;
else

{ cout << " matrix cannot be added \ n " ;

exist ( 0 ) ;

}

cout << " \ nInput matrix - A \n " ;
for ( i = 0 ; i <m ; i ++ )
{

for ( j = 0 ; j < n ; j + + )
cin >> a [i ] [ j] ;

}

cout << " \nMATRIX -A :" ;
for ( i = 0 ; i < m ; i + + ) // Print matrix A in matrix form.

{ cout << "/ n" ;

for ( j = 0 ; j < n ; j + + )

cout << " " << a [ i ] [ j ] ;
}

cout << " \ nInput matrix- B \ n ; . // Loop to accept matrix B.

for ( i = 0 ; i < p ; i + + )
{

for ( j = 0 ; j < q ; j + + )

cin>> b [ i ] [ j ] ;

}

cout < < " \ n MATRIX - B : " ;
for ( i = 0 ; i < p ; i + + ) // print matrix B in matrix form .

{ cout << " \ n " ;

for ( j = 0 ; j < q ; j ++)
cout << " " << b [ i ] [ j ] ;

}

for ( i = 0 ; i < m ; i ++ ) addiction of two matrix .

{

for ( j = 0 ; j < n ; j + + )

c [ i ] [ j ] = a [ i ] [ j ] ;

}

cout << " \ n The sum of two matrix is : \ n " ;

for. ( i = 0 ; i < m ; i + + )

{

cout << " \ n " ;
for ( j = 0 ; j < n ; j ++ )
cout << " " << c [ i ] [ j ] ;

}
return 0;
}


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