Hello everyone please solve this question
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,here is the answer of the given question
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sin6A + cos6A
= (sin^2A)3 + (cos^2A)3
= (sin^2A + cos^2A)(sin^4A – sin^2A cos^2A +cos4A)
= 1 (sin^4A – sin^2A cos^2A + cos^4A+2sin^2A cos^2A – 2sin^2A cos^2A)
= (sin^2A + cos^2A) – 3sin^2A cos^2A
= 1 – 3sin^2A cos^2A
= (sin^2A)3 + (cos^2A)3
= (sin^2A + cos^2A)(sin^4A – sin^2A cos^2A +cos4A)
= 1 (sin^4A – sin^2A cos^2A + cos^4A+2sin^2A cos^2A – 2sin^2A cos^2A)
= (sin^2A + cos^2A) – 3sin^2A cos^2A
= 1 – 3sin^2A cos^2A
AJAYMAHICH:
tysm dear
wlcm
which class student ??
10th
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