hello everyone !!! plss help me in this question . it's urgent please help as soon as you can ...........38 ml of most Nitrogen gas were collected at 27 degree Celsius and 74 6.5 mm pressure calculate the volume of the gas at 0 degree Celsius and 760 mm pressure aqueous tension at 27 degree celsius is to 26.5 mm
Answers
ANSWER
The volume of the gas is 33.6 bar.
Given:
\bold{V_1=38\ ml}V1
=38 ml
\bold{P_1=746.5 - 6.5 =740 \ mmHg = 0.98 \ bar}P1
=746.5−6.5=740 mmHg=0.98 bar
\bold{P_2=760 \ mmHg=1.01 \ bar}P2
=760 mmHg=1.01 bar
\bold{T_1=27^{\circ}\ C = 273+27^{\circ}\ C=300 \ K}T1
=27 ∘
C=273+27∘
C=300 K
\bold{T_2=0^{\circ}\ C = 273+0^{\circ}\ C=273 \ K}T2
=0∘
C=273+0∘
C=273 K
To find:
\bold{V_2=?}V2=?
Formula used:
\bold{\frac{P_{1} V_{1}}{T_{2}}=\frac{P_{2} V_{2}}{T_{2}}}
T2P1V1 = T2P2V2
Solution:
Now, the volume is given by the formula:
\bold{V_{2} = \frac{P_{1} V_{1} T_{2}}{P_{2} T_{1}}}V2
= P2T1P1V1T2
On substituting the know values, we get,
\bold{V_2=\frac{0.98\times38\times273}{1.01\times300}}V2 =
1.01×300
0.98×38×273
\bold{V_2=\frac{10166.52}{303}}V2
= 303
10166.52
The volume at 0 degree Celsius and 760 mmHg is
\bold{\therefore V_2=33.6 \ bar}∴V2