Question

Hello experts...❤

Please help me with the following series sum :

S= 1+ 1/3+ 1/5.... n terms.

Please don't ignore my question and try to solve it as fast as possible...

Best answer will be marked as Brainliest...

#Priya ;)

Answer 1

class ab
{
public static void main(int n)
{
int i;
double s=0.0;
for(i=1;i<=n;i+=2)
{
s=s+1/i ;
}
System.out.println(s);
}
}

Answer 2

Here, a=1,d=2,b=1,r=xa=1,d=2,b=1,r=x

SnSn=ab1−r+bdr(1−rn−1)(1−r)2−[a+(n−1)d]brn1−r=11−x+2x(1−xn−1)(1−x)2−[1+(n−1)(2)]xn1−x=11−x+2x(1−x)2−2x.xn−1(1−x)2−[1+2n−2]xn(1−x)=11−x+2x(1−x)2−2xn(1−x)2−[2n−1]xn(1−x)