Question

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Find the area of a triangular park whose sides are 40m, 32m,24m

Answer 1

$\huge\bf\red{ANSWER:-}$

Let the sides of ∆ ABC be a= 40m, b = 32cm, 24m

To find area we must use Heron's formula because we are not given the height.

Using Heron's formula, we get:-

semi perimeter = a+b+c/2

=40+32+24/2

= 48m

s-a=48-40=8m

s-b= 48-32= 16m

s-c= 48-24= 24m

Area of ∆ ABC= √s(s-a)(s-b)(s-c)

= √48×8×16×24

= 384 m^2

Therefore,

Area of the triangle is 384 m^2

Answer 2

$\huge\bf\purple{HOLA\:MATE}$

$<b> <i>$

Let the sides of ∆ ABC be a= 40m, b = 32cm, 24m

To find area we must use Heron's formula because we are not given the height.

Using Heron's formula, we get:-

semi perimeter = a+b+c/2

=40+32+24/2

= 48m

s-a=48-40=8m

s-b= 48-32= 16m

s-c= 48-24= 24m

Area of ∆ ABC= √s(s-a)(s-b)(s-c)

= √48×8×16×24

= 384 m^2

Therefore,

Area of the triangle is 384 m^2

HOPE THIS HELPS