Hello!!
Find the probability that a number chosen at random from the integers between 10 and 20 inclusive is a multiple of 5 or a multiple of 2.
Proper explanation required!!
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Answers
Answered by
8
hey! your answer↓
s:integers between 10 and 20
s={11,12,13,14,15,16,17,18,19}
n(s)=9
A:multiple of 5 or 2
A={12,14,15,16,18}
n(A)=6
P(A)=n(A)/n(s)
=6/9
=2/3
the probability of integers between 10 and 20 which are multiple of 5 or 2 is 2/3
B: multiple of 5
B={15}
n(B) =1
P(B) =1/9
C: multiple of 2
C={12, 14,16,18}
n(C) =4
P(C) =4/9
hope that it will help you
s:integers between 10 and 20
s={11,12,13,14,15,16,17,18,19}
n(s)=9
A:multiple of 5 or 2
A={12,14,15,16,18}
n(A)=6
P(A)=n(A)/n(s)
=6/9
=2/3
the probability of integers between 10 and 20 which are multiple of 5 or 2 is 2/3
B: multiple of 5
B={15}
n(B) =1
P(B) =1/9
C: multiple of 2
C={12, 14,16,18}
n(C) =4
P(C) =4/9
hope that it will help you
adi2129:
ur sample space is wrong
Answered by
1
:integers between 10 and 20
s={11,12,13,14,15,16,17,18,19}
n(s)=9
A:multiple of 5 or 2
A={12,14,15,16,18}
n(A)=6
P(A)=n(A)/n(s)
=6/9
=2/3
the probability of integers between 10 and 20 which are multiple of 5 or 2 is 2/3
B: multiple of 5
B={15}
n(B) =1
P(B) =1/9
C: multiple of 2
C={12, 14,16,18}
n(C) =4
P(C) =4/9
hope this answer helpful u
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