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Find the size of the angles of a parallelogram if one angle is 20° less than two is the smallest angle.
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Answer:
Let the smallest Angle be x
Other angle be = 2x-20
In parallelogram opposite angles are equal.
Sum of the consecutive interior angles = 180°
X+ (2x-20)= 180°
3x-20°=180°
3x=180+20
3x=200
X= 200/3
X= 66.666...= 66.7°(approx.)
Smallest angle= 66.7°
Other angle = 2x-20
= 2x66.7-20= 133.4-20= 113.4°
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