Hello Friend...
How r u now my question is here...
"If cos 7A=sin (A-6) where 7A is an acute angle .Find the value A????"...
Please answer...
SunnyPatel:
answer is 12
Answers
Answered by
18
Hey Mate :
~~~~~~~~
Here is your answer :
____________________________
Given,
7A is an acute angle.
cos 7A = Sin ( A - 6 )
Sin ( 90 - 7A ) = Sin ( A - 6 )
90 - 7A = A - 6
90+ 6 = A + 7A
96 = 8A
A = 96/8
A = 12
HOPE THIS HELPS U...
~~~~~~~~
Here is your answer :
____________________________
Given,
7A is an acute angle.
cos 7A = Sin ( A - 6 )
Sin ( 90 - 7A ) = Sin ( A - 6 )
90 - 7A = A - 6
90+ 6 = A + 7A
96 = 8A
A = 96/8
A = 12
HOPE THIS HELPS U...
right
incomplete answer bro cos A also satify the value 44°
thanks Bro
I was very busy
Answered by
8
hi mates!!
here ur answer is
given
cos 7A=sin(A-6)
since 7A is an acute angle
since(90-7A)=sin(A-6)
(90-7A)=(A-6)
A=96
A=12degree
HOPE THIS WILL HELP U
here ur answer is
given
cos 7A=sin(A-6)
since 7A is an acute angle
since(90-7A)=sin(A-6)
(90-7A)=(A-6)
A=96
A=12degree
HOPE THIS WILL HELP U
incomplete answer as A can be 44° also
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