Question

Hello friend . Please answer it fast.​

Answer 1

Answer with explanation :

(i) "M" is the mid point

BM = AM,

it's also the mid point of DC then

DM = MC

And AD = DB, Hence the length is same

Hence, we can say that ΔAMC ≈ ΔBMD (sorry, that sign isn't available on my keyboard, that's why I used ≈, please write the correct sign) Proved

(ii) / DBC is as right angles triangle and

DC² = DB² + BC² (they're pythagoras)

• hence, / B = 90°, Proved

(iii) M is the mid point of AB and DC. hence,

DM = MC & AB = BM

DC = AB (after all they're in the same length)

Also, AC = DB , / B = / C = 90°

By SAS Axiom, ΔDBC ≈ ΔABC, Proved

(iv) ΔDBC ≈ ΔACB, CM = DC/2 (write fraction)

• DC = AB (ΔDBC ≈ ΔACB )

Hence, CM = AB/2 (write in fraction)

CM =½ AB, proved

These were your answers with full explaination, I just want brainliest, please mark me brainliest :)