Math, asked by MissWorld1, 1 year ago

Hello friends.........

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Answered by Rajusingh45
3
Hello friends

____________________________

Given:

Amount (A) = 5280 rupees.

Principal (P) = 4000 rupees

Rate of interest (R) = 8% per annum

We have to find,

Period (N) = ??


We know that,

Amount = Principal + S. I

S.I = A - P

By using this formula we get,

S.I = A - P

S.I = 5280 - 4000

S.I = 1280

And we know that,

S.I = P x N x R/100

By putting the given values we get,

1280 = 4000 x N x 8/100

N = 1280 x 100/4000 x 8

N = 4 years..


Thanks...


:)
Answered by kushanaanandp4ac8a
2
Hey!

Principal=4000Rs.

Amount=5280Rs.

Time= t years.

Rate of interest= 8% per year.

SI =A-p
Also SI=( p*r*t)/100.
A-p =( p*r*t)/100.

5280-4000=( 4000*8*t)/100.

1280=32000t/100.

1280=320t

t= 1280/320
= 4years= option 2.

Hope it helps.
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