Question

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Answer 1

Solution:

Given: ΔABC ≈ ΔBDC

So, By using B.P.T

$\frac{AB}{BD} =  \frac{BC}{DC} =  \frac{AC}{BC}$

$\frac{AB}{BD} =  \frac{BC}{DC}$

Using pythagoreas theorm:

AB² + BC² = AC²

=> 9 + 16 = AC²

=> AC = √25 = 5 units

∴DC = 5-2 = 3 units

NOW,

$\frac{3}{BD} = \frac{4}{3}$

∴ BD = 9/4 Units

_______________________

Amrit_________

Answer 2

Answer:

Given: AABC = ABDC

So, By using B.P.T

AB - BC - AC BC

BD

DC

AB BD BC DC

Using pythagoreas theorm:

AB² + BC² = AC²

=> 9 + 16 = AC²

=> AC = √25 = 5 units

..DC = 5-2= 3 units

NOW,

BD = }} 4 3

..BD = 9/4 Units