Question

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A question for you all

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Answer 1

Given: $\frac{6(8)^{n + 1} + 16 (2)^{3n-2} }{10( 2)^{3n + 1} - 7(8)^n}$

$\frac{2^1 * 2^{3(n + 1)} * 2^4 * 2^{3n - 2} }{2^1 * 5 * 2^{3n + 1} - 7 * 8^n}$

$\frac{3 * 2^{3(n + 1) + 1} * 2^{3n - 2 + 4} }{5 * 2^{3n + 1 + 1} - 7 * 8^n }$

$\frac{3 * 2^{3n + 4} * 2^{3n + 2} }{5 * 2^{3n + 2} - 7 * 8^n }$

$\frac{3 * 2^{3n + 4} + 2^{3n + 2} }{5 * 2^{3n + 2} - 7 * 8^n}$

$\frac{ 2^{3n + 2}(3 * 2^2 + 1)}{5 * 2^{3n + 2} - 7 * 8^n }$

$\frac{13 * 2^{3n + 2} }{5 * 2^{3n + 2} - 7 * 8^n}$

$\frac{ 2^{3n} (13 * 2^2)}{5 * 2^{3n} * 2^2 - 7 * 2^{3n} }$

$\frac{ 2^{3n}(13 * 2^2)}{ 2^{3n}(5 * 2^2 - 7) }$

$\frac{13 * 4}{5 * 4 - 7}$

$\frac{52}{20 - 7}$

$\frac{52}{13}$

4.

Hope this helps!

Answer 2

Answer:

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Step-by-step explanation:

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