Math, asked by ShuchiRecites, 1 year ago

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A question for you all

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Answers

Answered by siddhartharao77
2
Given:  \frac{6(8)^{n + 1} + 16 (2)^{3n-2}  }{10( 2)^{3n + 1} - 7(8)^n}

 \frac{2^1 *  2^{3(n + 1)}  * 2^4 *  2^{3n - 2} }{2^1 * 5 *  2^{3n + 1} - 7 * 8^n}

 \frac{3 *  2^{3(n + 1) + 1} *   2^{3n - 2 + 4}   }{5 *  2^{3n + 1 + 1} - 7 * 8^n }

 \frac{3 *  2^{3n + 4} *  2^{3n + 2}  }{5 *  2^{3n + 2} - 7 * 8^n }

 \frac{3 *  2^{3n + 4} +  2^{3n + 2} }{5 *  2^{3n + 2}  - 7 * 8^n}

 \frac{ 2^{3n + 2}(3 * 2^2  + 1)}{5 *  2^{3n + 2} - 7 * 8^n }

 \frac{13 *  2^{3n + 2} }{5 *  2^{3n + 2}  - 7 * 8^n}

 \frac{ 2^{3n} (13 * 2^2)}{5 *  2^{3n} * 2^2 - 7 *  2^{3n}  }

 \frac{ 2^{3n}(13 * 2^2)}{ 2^{3n}(5 * 2^2 - 7) }

 \frac{13 * 4}{5 * 4 - 7}

 \frac{52}{20 - 7}

 \frac{52}{13}

4.

Hope this helps!

ShuchiRecites: In which standard do u study
ShuchiRecites: By the way I have came in 9th and thanks a lot once again for ur answer
ShuchiRecites: Good night
siddhartharao77: Gud n8...
ShuchiRecites: Can I ask one question
ShuchiRecites: In this solution
ShuchiRecites: In second step you didn't mentioned 3
ShuchiRecites: 6 = 2 × 3
siddhartharao77: I forgot.Sorry
ShuchiRecites: Its ok
Answered by pdp27263
4

Answer:

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Step-by-step explanation:

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