English, asked by amanjatti0055, 7 months ago

hello friends ajj meri saniya frnd ne apne app ko mrne ki koshish ki,, vo kamjaab bhi ho gyi thi but sahi vkht pe oske uncle ne hospital le jaker bacha liya soooo saad ​

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Answers

Answered by Anonymous
31

Answer:

\boxed{\begin{array}{|c|c|c|c|}  {1-4}\Large\sf {Ionic\:Compounds} & \sf \Large {Chemical\:Formula} & \Large \sf{Melting\:point_{(k)}} & \Large\sf {Boiling\:point_{(k)}}\\ &&& \\  {1-4} \sf Sodium\:Chloride & \sf NaCl & 1074 & 1686 \\ &&& \\ {1-4} \sf Lithium\:Chloride & \sf \sf LiCl & 887 & 1600 \\ &&& \\ {1-4} \sf Calcium\:Chloride & \sf CaCl_2 & 1045 & 1900 \\ &&& \\ {1-4} \sf Calcium\:Oxide & \sf CaO & 2850 & 3120 \\ &&& \\ \ {1-4} \sf Magnesium\:Chloride & \sf MgCl_2 & 981 & 1685 \\ &&& \\ {1-4} \end{array}}

Answered by Sankalp050
38

Explanation:

 { {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}

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