Question

Hello friends !!

Answer this :-

=>A 150 g ball , travelling at 30m/s , strikes the palm of a player's hand and is stopped in 0.05 second.Find the Force exerted by ball on the hand .

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Answer 1

Give. that the ball is travelling with a speed of 30m/s

It is stopped in 0.05 seconds by the force applied by the player.

To find :- Force.

We have to find the acceleration first in order to find out the force.

We know that, acceleration = (v - u)/t

Since the ball is stopped, v = 0
u = 30
t = 0.05

=> acceleration = (0 - 30)/0.05

= -30/0.05

= - 600 m/s²

So, from the second law of Newton, we know

Force = mass × acceleration

mass = 150 g = 0.15 kg

acceleration = - 600 m/s²

=> Force = - 600 × 0.15

=> Force = -90 Newton

Negative symbol means that the force is applied in opposite direction of the motion.

Here, -90 N is the force applied by the player on the ball. The question asks for the force applied by the ball on the player.

So, following the third law of motion, the force that should be applied by ball would be same but opposite direction of the force applied by the player. Hence, the answer is + 90 N.

Answer 2

$\huge\bf\green {Hey \: there!}$



▶ Given :


i) Mass of a ball ( m ) = 150 g = 0.15 kg


ii) Initial velocity of the ball ( u ) = 30 m / s


iii) Final velocity of the ball ( v ) = 0 m / s


iv) The player's hand stops the ball in 0.05 seconds




▶To Find :



Force exerted by ball on the hand



▶ According to the Question :



Initial momentum of the ball = mu


= 0.15 × 30


= 4.5 kg m / s



Final momentum of the ball = mv


= 0.15 × 0


= 0 kg m / s



Change in momentum of the ball = Final momentum - Initial momentum


= 0 - 4.5


= - 4.5 kg m / s



Rate of change of momentum = - 4.5 / 0.05


= - 45 × 100 / 5 × 10


= - 90 N



This is the force exerted by the ball on the hands



$\large {\boxed {\boxed {\pink {\sf {So, the \: force \: exerted \: by \: the \: balls \: on \: the \: hands = 90 \: N}}}}}$



✔✔ Hence, it is solved ✅✅




$\mathbb {\huge {\fcolorbox {yellow}{green}{Hope It Helps}}}$




$\huge\bf\red{\#BeBrainly}$