Physics, asked by Muskan1101, 1 year ago

Hello friends!!

Answer this :-

"How long will it take a Force of 10N to stop a mass of 2.5 kg which is moving at 20m/s ? "

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Answers

Answered by IITGENIUS1234
16

\huge\bf\green  {Hey \:  there!}



▶ Given :


i) Force = - 10 N ( Since the force is acting in the opposite direction of the motion )


ii) Mass = 2.5 kg


iii) Initial velocity ( u ) = 20 m / s


iv) Final velocity ( v ) = 0 m / s



▶ To Find :



Time taken for the force to stop the body




▶ We know that :



Force ( F ) = m × ( v - u ) / t


=> - 10 = 2.5 × ( 0 - 20 ) / t


=> - 10 = 2.5 × - 20 / t


=> - 10 = - 50 / t


=> t = - 50 / - 10


=> t = 5 seconds



\large {\boxed {\boxed {\pink {\sf {Hence, Time  \: taken \:  for \:  the \:  force \:  to  \: stop \:  the  \: body = 5  \: seconds}}}}}



✔✔ Hence, it is solved ✅✅




\mathbb {\huge {\fcolorbox  {yellow}{green}{Hope It Helps }}}



\huge\bf\red {\#BeBrainly}

Anonymous: Great ✌
IITGENIUS1234: thanks to all
Answered by BrainlyVirat
25
Here's the answer

Mass of the body = 2.5 kg

Initial velocity ( u )= 20 m/s

Final velocity ( v ) = 0 m/s

Force ( F ) = 10 N

We know that,


 \sf{Acceleration (a) =  \frac{F}{m}}

 \sf{ =  \frac{10}{2.5}}

 \sf{ = 4 \: m/s {}^{2}}

Now,

v > u
So ,
Acceleration has negative (-) sign

a = (- 4) m/s^2

Now

 \sf{t =  \frac{v - u}{a}}


 \sf{ t =  \frac{0 - 20}{ - 4}}

 \sf{t =  \frac{ - 20}{ - 4}}

 \sf{t = 5 \: s}


Thus ,

It will take 5 seconds for a Force of 10N to stop a mass of 2.5 kg which is moving at 20m/s.

Thanks!!


Anonymous: Great ans ✌
BrainlyVirat: Thank you ✌️❤️
Anonymous: Welcome ☺
BrainlyVirat: ^_^
BrainlyVirat: Tysm :)
sanya16185: fab❤️
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