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Answer this :-
"How long will it take a Force of 10N to stop a mass of 2.5 kg which is moving at 20m/s ? "
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Answers
Answered by
16
▶ Given :
i) Force = - 10 N ( Since the force is acting in the opposite direction of the motion )
ii) Mass = 2.5 kg
iii) Initial velocity ( u ) = 20 m / s
iv) Final velocity ( v ) = 0 m / s
▶ To Find :
Time taken for the force to stop the body
▶ We know that :
Force ( F ) = m × ( v - u ) / t
=> - 10 = 2.5 × ( 0 - 20 ) / t
=> - 10 = 2.5 × - 20 / t
=> - 10 = - 50 / t
=> t = - 50 / - 10
=> t = 5 seconds
✔✔ Hence, it is solved ✅✅
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Answered by
25
Here's the answer
Mass of the body = 2.5 kg
Initial velocity ( u )= 20 m/s
Final velocity ( v ) = 0 m/s
Force ( F ) = 10 N
We know that,
Now,
v > u
So ,
Acceleration has negative (-) sign
a = (- 4) m/s^2
Now
Thus ,
It will take 5 seconds for a Force of 10N to stop a mass of 2.5 kg which is moving at 20m/s.
Thanks!!
Mass of the body = 2.5 kg
Initial velocity ( u )= 20 m/s
Final velocity ( v ) = 0 m/s
Force ( F ) = 10 N
We know that,
Now,
v > u
So ,
Acceleration has negative (-) sign
a = (- 4) m/s^2
Now
Thus ,
It will take 5 seconds for a Force of 10N to stop a mass of 2.5 kg which is moving at 20m/s.
Thanks!!
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