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INΔ ABC AND Δ DEF
AB = DE (GIVEN)
ANGLE A = ANGLE D (BOTH IS 90*)
SINCE , BF = CE(GIVEN)
ADD , CF AT BOTH SIDE
WE GET , BF+CE =CE+ CF
THEN , BC = EF (PROVED )
THEREFORE Δ ABC ≅ΔDEF(BY SAS CRITERIA)
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