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A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .


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Answer 1

Question :

A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .  

Given information :

The boy claps every second.

So in 1 s he claps 1 time .

Time for echo

He moves until the echo is heard midway between the claps.

Hence the echo is heard in 0.5 s

This is because he claps in 1 s and the midway will be 1/2 s = 0.5 s.

Formula for speed

Speed = distance / time

Time he heard the echo = 0.5 s

Distance travelled by the echo

Let Distance from the surface be d.

The distance traveled by echo is 2 d since it has to move twice from the source to reflecting surface and from the reflecting surface to the source.

Speed

Speed given is = 360 m/s

Distance

Speed = distance / time

⇒ 360 m/s = 2 d / 0.5 s

⇒ 2 d = 360 m/s × 0.5 s

⇒ 2 d = 180 m

⇒ d = 180 m / 2

⇒ d =90 m

ANSWER:

Distance is 90 m

Answer 2

Speed = distance/time

t = 0.5s

let distance be 2d

360 = 2d/0.5

= 2d=180

= d=180/2

= d=90

The distance is 90m. Hope it helps