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A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .
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Question :-
A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .
ANSWER :-
90 m
Step by Step :-
Given :
The boy claps every second.
So in 1 s he claps 1 time .
Time
He moves until the echo is heard midway between the claps.
Hence the echo is heard in 0.5 s
This is because he claps in 1 s and the midway will be 1/2 s = 0.5 s.
Formula
Speed = distance / time
Time he heard the echo = 0.5 s
Let Distance from the surface be d.
The distance traveled by echo is 2 d since it has to move twice from the source to reflecting surface and from the reflecting surface to the source.
Speed given is = 360 m/s
Calculate the distance
Speed = distance / time
= > 360 m/s = 2 d / 0.5 s
= > 2 d = 360 m/s × 0.5 s
= > 2 d = 180 m
= > d = 180 m / 2
= > d =90 m
Sorry if wrong =_=
Speed = distance/time
t = 0.5s
let distance be 2d
360 = 2d/0.5
= 2d=180
= d=180/2
= d=90
The distance is 90m. Hope it helps