Physics, asked by IITGENIUS1234, 1 year ago

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A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .

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KingOMac1: good question

Answers

Answered by Anonymous
4

Question :-

A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .


ANSWER :-

90 m


Step by Step :-


Given :

The boy claps every second.

So in 1 s he claps 1 time .


Time

He moves until the echo is heard midway between the claps.

Hence the echo is heard in 0.5 s

This is because he claps in 1 s and the midway will be 1/2 s = 0.5 s.


Formula


Speed = distance / time

Time he heard the echo = 0.5 s

Let Distance from the surface be d.

The distance traveled by echo is 2 d since it has to move twice from the source to reflecting surface and from the reflecting surface to the source.

Speed given is = 360 m/s


Calculate the distance


Speed = distance / time

= > 360 m/s = 2 d / 0.5 s

= > 2 d = 360 m/s × 0.5 s

= > 2 d = 180 m

= > d = 180 m / 2

= > d =90 m


Sorry if wrong =_=

Answered by Anonymous
0

Speed = distance/time

t = 0.5s

let distance be 2d

360 = 2d/0.5

= 2d=180

= d=180/2

= d=90


The distance is 90m. Hope it helps

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