Chemistry, asked by IITGENIUS1234, 1 year ago

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Find the equivalent weight of both oxidising agent and reducing agent in the below equation :


\sf {HNO_3 + Cu \longrightarrow Cu(NO_3)_2 + NO_2 + O_2 }


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Answered by deepu7575
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In the reaction CuSO4+Zn=Cu+ZnSO4:
Oxidation:- Zinc. (Zn)
Reduction:-Copper. (Cu)
Oxidising agent:-Copper. (Cu)
Reducing agent:-Zinc. (Zn)
In the reaction Cu+2AgNO3=Cu (NO3)2+Ag:
Oxidation:Copper(Cu).
Reduction :Silver (Ag).
Oxidising agent :Silver (Ag)
Reducing agent :Copper (Cu)...

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