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We know that : Function f : R ==> R defined by f(x) = [x] assumes the Greatest Integer which is Less than (or) Equal to x
For Example, Consider : x = 2.9
As [x] = 2 for all 2 ≤ x ≤ 3
⇒ [2.9] = 2 (Greatest Integer less than or Equal to x)
Now, Consider the Given Question :
✿ f(x) = cos[π]x + cos[πx]
We know that : The Value of π is 3.14
As [x] = 3 for all 3 ≤ x ≤ 4
⇒ [π] = [3.14] = 3
We know that : Value of π² = 9.869
As [x] = 4 for all 4 ≤ x ≤ 5
[y] is the integral part of y
We know that π is 180° but that is the angular part.
For π to be an integer we need to consider π as 3.14
But 3.14 is a decimal value.
Round it of to the nearest integer.
3.14 ................................... 3
We have to take π as 3 in the expression.
So put the values :
f ( x ) = cos [ π ] x + cos [ π x ]
Finding f ( π / 2 )
f ( π / 2 ) = cos [ π ] π / 2 + cos [ π × π/2 ]
Within the braces [] π = 3
==> f ( π / 2 ) = cos 3 π / 2 + cos [ 3.14 × 3.14/2 ]
= cos 3 π / 2 + cos [ 9.something /2 ]
= cos 3 π / 2 + cos [ 4.something ]
But cos 3 π / 2 = cos 270° = cos ( 180 ° + 90° )
= - cos 90°
= 0
So : f ( π /2 ) = cos [ 4 . something ]
Round again to cos 4
Hence f ( π / 2 ) = cos 4
ANSWER :
Option : C
Hope it helps :-)
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