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The population of a town is 50000. If the annual emigration rate is 6% and the annual immigration rate is 4%, calculate the population after two years.
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Answer:
48020
Step-by-step explanation:
First of all :
Emigration is the migration of people away from town .
Immigration is the migration into the town.
Population = 50,000 .
First year
Emigration = 6% of 50,000
= 6% × 50,000
= 6/100 × 50,000
= 6 × 500
= 3,000
Immigration = 4 % of 50,000
= 4/100 × 50,000
= 1/25 × 50,000
= 2000
Total no. of people change = 2000 - 3000
= - 1000
No .of people becomes = 50,000 - 10,000
= 49,000
Second year
Emigration = 6% of 49,00
= 6/100 × 49000
= 6 ×490
= 2940
Immigration = 4% of 49,000
= 4/100 × 49,000
= 4 ×490
= 1960
Total people change = 1960 - 2940
= -980
Number of people now = 49,000 - 980
= 48,020
Hope it helps -__^
You looking for this one
Here you Go
6% of 50,000 is 3000
4% of 50,000 is 2000
Emigration means they are leaving the town. So -3000
Immigration means they are coming in. So +2000
-3000+2000= -1000
After first year the total is 49000
6% of 49000 is 2940
4% of 49000 is 1960
-2940+1960= -980
So 49000-980= 48020.
hope it helps