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Topic : Critical thinking
A cow produces a calf at the beginning of every year. The young cow will become productive and conceive in the fourth year and gives birth to another calf the beginning of every year, starting from the following year. How many cows will be there in the eighth year ?
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Answered by
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The cow produces calf every year .
After one year
The cow produced one calf .
Hence number of cows = 1 + 1 = 2
After two years
The cow produced another calf
Number of cows = 2 + 1 = 3
After three years
Another calf is produced.
Number of cows = 3 + 1 = 4
After four years.
In the fourth year the first born cow can produce a cow.
Hence 2 cows are produced in this year.
Number of cows = 4 + 2 = 6
After five years.
In the fifth year the second cow can produce another baby.
Hence 3 will be produced .
This sequence will follow upto 8 years
So : 6 + 3 + 4 + 5 will be the number of cows after 7 years.
= 9 + 4 + 5
= 13 + 5
= 18
Hence 18 cows will be there at the beginning of the 8 th year.
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Answered by
9
After one year
The cow produced one calf .
Hence number of cows = 1 + 1 = 2
After two years
The cow produced another calf
Number of cows = 2 + 1 = 3
After three years
Another calf is produced.
Number of cows = 3 + 1 = 4
After four years.
In the fourth year the first born cow can produce a cow.
Hence 2 cows are produced in this year.
Number of cows = 4 + 2 = 6
After five years.
In the fifth year the second cow can produce another baby.
Hence 3 will be produced .
This sequence will follow upto 8 years
So : 6 + 3 + 4 + 5 will be the number of cows after 7 years.
= 9 + 4 + 5
= 13 + 5
= 18
Hence 18 cows will be there at the beginning of the 8 th year.
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