Math, asked by IITGENIUS1234, 1 year ago

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Topic : Critical thinking


A cow produces a calf at the beginning of every year. The young cow will become productive and conceive in the fourth year and gives birth to another calf the beginning of every year, starting from the following year. How many cows will be there in the eighth year ?


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Answered by Anonymous
12

The cow produces calf every year .


After one year

The cow produced one calf .

Hence number of cows = 1 + 1 = 2


After two years

The cow produced another calf

Number of cows = 2 + 1 = 3


After three years

Another calf is produced.

Number of cows = 3 + 1 = 4


After four years.

In the fourth year the first born cow can produce a cow.

Hence 2 cows are produced in this year.

Number of cows = 4 + 2 = 6


After five years.

In the fifth year the second cow can produce another baby.

Hence 3 will be produced .

This sequence will follow upto 8 years

So : 6 + 3 + 4 + 5 will be the number of cows after 7 years.

= 9 + 4 + 5

= 13 + 5

= 18

Hence 18 cows will be there at the beginning of the 8 th year.


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Answered by Anonymous
9

After one year

The cow produced one calf .

Hence number of cows = 1 + 1 = 2


After two years

The cow produced another calf

Number of cows = 2 + 1 = 3


After three years

Another calf is produced.

Number of cows = 3 + 1 = 4


After four years.

In the fourth year the first born cow can produce a cow.

Hence 2 cows are produced in this year.

Number of cows = 4 + 2 = 6


After five years.

In the fifth year the second cow can produce another baby.

Hence 3 will be produced .

This sequence will follow upto 8 years

So : 6 + 3 + 4 + 5 will be the number of cows after 7 years.

= 9 + 4 + 5

= 13 + 5

= 18

Hence 18 cows will be there at the beginning of the 8 th year.



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