Question

hello friends bgfghgfffbfdfbbbbv.If A and B are acute angles such that sinA = cosB, then A+B is equal to​

Answer 1

Step-by-step explanation:

A+B=90degree

A=90-B

Apply sin on both sides

sinA=Sin(90-B)

sinA=cosB

Ans is 90 degrees

Answer 2

Given :

• sin A = cos B

To Find :

• A + B = ?

Solution :

We are given,

sin A = cos B

Now, we know that,

$\Large \underline{\boxed{\bf{ cos \theta = sin (90^{\circ} - \theta) }}}$

$\sf : \implies sin A = sin (90^{\circ} - B)$

$\sf : \implies A = 90^{\circ} - B$

$\sf : \implies A + B = 90^{\circ}$

$\Large \underline{\boxed{\bf{A + B = 90^{\circ}}}}$

Therefore, A + B = 90°