Question

HELLO FRIENDS..

Can u solve the attachment

PLEASE NO SILLY ANSWERS..

Answer 1

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GIVEN:- ABC is a triangle,PQ ll BC; AD is the median which cuts PQ at R

TO PROVE:-AD bisects PQ ll BD

PROOF:- IN ∆ABD;PR ll BD.
AP/RD = RD

IN∆ ACD , RQ ll DC

.. AR/RD = AQ/QC

IN ∆ APR and ∆ABD

Angle APR = Angle ABD ( corresponding angles)

Angle APR and Angle ADB (corresponding angles)

∆APR is similar to ∆ABD (AA COMMAN)

AP= PR =AR

SIMILARLY ∆ARQ IS SIMILAR TO ∆ADC

AQ/AC = AR/AD = RQ/DC.

ACCORDING TO EQUATION 1 AND 2..

AR/ AD = PR/ BD =RQ/DC

RD = DC( GIVEN )
PQ = RQ

AB bisected PQ at R ( proved)
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THANKS♡♡

Answer 2

hey there➡️

here ur answer which i wrote and attached for u❗

hope this helps u✅✔️✅✔️

be brainly❤️