Question

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Find time when, Principal = $ 700 , Rate=18% p.a. , Simple interest = $78.


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Answer 1

$\mathfrak{\huge{\underline{Solution:}}}$

$\textbf{\huge{\underline{Given:}}}$

$\rm \: Principal \: (P)= Rs \: 700$

$\rm \: Rate \: (R)= 18\%$

$\rm \: Simple \: Interest \: ( S.I) = Rs \: 78$

To find Time when S.I, Principal and Rate are given :

$\rm \: Time = \dfrac{SI \times100 }{P \times R}$

$\rm \: Time = \dfrac{78 \times 1 \cancel0 \cancel0}{7 \cancel0 \cancel0 \times 18}$

$\rm \: Time = \cancel \dfrac{78}{126}$

$\rm \: Time = \dfrac{13}{21}$

$\mathfrak{\huge{\underline{Verification:}}}$

$\rm \: S.I = \dfrac{P \times R \times T}{100}$

$\rm \: S.I = \dfrac{700 \times 18 \times13 }{21 \times 100}$

$\rm \: S.I = \dfrac{700 \times 18 \times13 }{21 \times 100}$

$\rm \: S.I = \cancel \dfrac{163800}{2100}$

$\rm \: S.I = Rs \: 78$

Hence,Verified!!

Answer 2

$\bf{\Huge{\underline{\boxed{\rm{\red{ANSWER\::}}}}}}$

Given:

• Principal,[P]= Rs.700
• Rate,[R]= 18% per annum
• Simple Interest,[S.I]= Rs.78

To find:

The time of Interest.

$\bf{\Large{\underline{\sf{\green{Explanation\::}}}}}$

We know that formula of Simple Interest= $\frac{P*R*T}{100}$

&

We can find time then formula formed;

⇒ Time= $\frac{S.I.*100}{P*R}$

Therefore,

⇒ Time= $\frac{78*100}{700*18}$

⇒ Time= $\frac{78*\cancel{100}}{7\cancel{00}*18}$

⇒ Time= $\frac{78}{126}$

⇒ Time= $\frac{\cancel{78}}{\cancel{126}}$

⇒ Time= $\frac{13}{21} \:years$

⇒ Time= 13/21 years