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Answered by
2
Answer:
let triangle ABC=x
triangleBDE+triangleCFD+triangleBDC+triangleABC=360°.
=70°+30°+70°+x=360°.
=170°+x=360°.
=x=360°-170°
x=190°;triangle ABC=190°
therefore the area of triange ABC in cm^2 is equal to 190°.
Answered by
2
Answer:
let triangle ABC is equal to X
triangle BDE. + triangle CFD + triangle bdc + triangle ABC is equal to 360 degree
70+30+70+x=360
=170+x=360
==x=360-170
===X=190
therefore the area of triangle ABC is 1 90 degree
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