Math, asked by Anonymous, 10 months ago

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Solve this Question.....
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Answered by Anonymous
2

Answer:

let triangle ABC=x

triangleBDE+triangleCFD+triangleBDC+triangleABC=360°.

=70°+30°+70°+x=360°.

=170°+x=360°.

=x=360°-170°

x=190°;triangle ABC=190°

therefore the area of triange ABC in cm^2 is equal to 190°.

Answered by ABHISHEK851101
2

Answer:

let triangle ABC is equal to X

triangle BDE. + triangle CFD + triangle bdc + triangle ABC is equal to 360 degree

70+30+70+x=360

=170+x=360

==x=360-170

===X=190

therefore the area of triangle ABC is 1 90 degree

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