Question

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$\sf\: the\: roots\:of\:2x^{2}+x+3=0\: are$

Answer: $\frac{-1+-i\sqrt{23}}{4}$

Answer 1

Hi... ✌✌

✨✨Here's your answer... ✌✌✨✨⬆⬆⬆

hope it helps you...... ❤❤

Answer 2

hey mate here is your answer ✌♥✌♥✌

2x²+X+3=0

so D=b²-4ac

=1²-4(2)(3)

=1-24

=-23

so by applying quadratic formula

X=(-b+-√D)/2a

=(-1+-√-23)/2(2)

=(-1+-i√23)/4.......... where i=√-1

so X={(-1+i√23)/4,(-1-i√23)/4}

hope it will be helpful to you ✔✔

mark me brainliest ✌✌✌✌