Question

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The taxi charges in Hyderabad are fixed, along with the charge for the distance covered. For a distance of 10 km., the charge paid is D220. For a journey of 15km. the charge paid is D310.
i. What are the fixed charges and charge per km?
ii. How much does a person have to pay for travelling a distance of 25 km?

Answer 1

☺️GOOD MORNING ☺️

✌️✌️Hey mate,

 Let fixed charge be x

And charge per km be y

So,  x+10y=220                  (1)

and  x+15y=310                    (2)

solving the equations,

equation(2)-equation(1)

           x+15y  - x-10y=310 -220

                           5y =90

                             y=Rs.18

put value of y in equation(1)

x+10*18=220

      x=220-180

      x=Rs.40  

We have

y=Rs18, x=Rs 40

For a distance of 25 km,

A person have to pay (40+25*18)=Rs 490.

Hope it helps.

Thanks

Nice to help you ✌️✌️

Answer 2

Hello!!

Solution:

Let fixed charge be p

And charge per km be q

So,  p + 10q = 220    ....    (1)

and  p + 15q = 310    ....    (2)

Solving the equations,

=> equation(2) - equation(1)

           p+15q  - p - 10q = 310 -220

                           5q =90

                             q=Rs.18

put value of q in equation(1)

p+10*18=220

      p=220-180

      p=Rs.40  

We have

q=Rs18, p=Rs 40

For a distance of 25 km,

A person have to pay (40+25*18)=Rs 490.

Hope it helps!