Question

hello friends...Height and Distance Quest.......class 10th.....
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Solve it on an attachment
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$tan45 = 1 \\ sin45 = \frac{1}{ \sqrt{2} } \\ sin30 = \frac{1}{2} \\ tan30 = \frac{1}{\sqrt{3} }$
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Answer 1

$(good \: \: question \: \: harshit \: ) \\ |here \: is \: ur \: ans \: \: \: \: hope \: it \: helps \: uh \: |$

please mark as brainliest

Answer 2

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