hello friends.... is there anyone who can solve this question.....
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Answered by
1
<C = 3 <B = 2( <A + <B)
From (1) and (2)
<C = 3 <B --------(1)
From (2) and (3)
3 <B = 2<A + 2<B
=> 2<A =3 <B - 2<B
=> 2<A = <B
=> <A = <B/2 ----------(2)
Now,
By angle sum property of triangle,
<A +<B + <C = 180°
=> <B/2 +<B + 3<B = 180°
=> ( <B + 2<B + 6<B) / 2 = 180°
=> 9<B = 360°
=> <B = 40°
--------------------
<A = 40 /2
<A = 20°
-------------------
<C = 3<B
<C = 3× 40
<C = 120°
From (1) and (2)
<C = 3 <B --------(1)
From (2) and (3)
3 <B = 2<A + 2<B
=> 2<A =3 <B - 2<B
=> 2<A = <B
=> <A = <B/2 ----------(2)
Now,
By angle sum property of triangle,
<A +<B + <C = 180°
=> <B/2 +<B + 3<B = 180°
=> ( <B + 2<B + 6<B) / 2 = 180°
=> 9<B = 360°
=> <B = 40°
--------------------
<A = 40 /2
<A = 20°
-------------------
<C = 3<B
<C = 3× 40
<C = 120°
Answered by
5
<C = 3 <B = 2( <A + <B)
From (1) and (2)
<C = 3 <B --------(1)
From (2) and (3)
3 <B = 2<A + 2<B
=> 2<A =3 <B - 2<B
=> 2<A = <B
=> <A = <B/2 ----------(2)
Now,
By angle sum property of triangle,
<A +<B + <C = 180°
=> <B/2 +<B + 3<B = 180°
=> ( <B + 2<B + 6<B) / 2 = 180°
=> 9<B = 360°
=> <B = 40°
--------------------
<A = 40 /2
<A = 20°
-------------------
<C = 3<B
<C = 3× 40
<C = 120°
hope it helped ❤️
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