Question

Hello friends, please answer my this question fast….
It is of class 10 science chapter 12 electricity…..
If 2*10-3 J of work is done in moving a particle carrying a charge of 10*10-6 coulomb from infinity to a point P. What will be the potential at point P?

Answer 1

Answer:

0.2 x 10^3 volt

Explanation:

We know that potential at any point is equal to amount of workdone in bring 1 unit charge from infinity to any point.

V = w/q

Given,

w = 2 x 10^-3 J

q = 10 x 10^-6 J

V = w/q

=> V = 2 x 10^-3 / 10 x 10^-6

=> V = 0.2 x 10^3 v

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Answer 2

Answer:

I also got it right.........