Question

Hello friends
Please help me in this problem
Correct answer along with proper explanation will be marked as the brainliest answer ​

Answer 1

DO NOT replace the value of x. Only a computer can do the job.

This kind of problem isn't solved by substitution, it makes the situation worse.

The root is γ.

→ γ²+2γ+6=0 --- (1)

Change the sight. You may expand the brackets first.

(We can do it easily if we do first×last and second×third.)

$\boxed{(\gamma^2+7\gamma+10)(\gamma^2+7\gamma+12)}$

Now we can use (1):

$\boxed{(5\gamma+4)(5\gamma+6)}$

Expanding again:

$\boxed{25\gamma^2+50\gamma+24}$ → $\boxed{25(\gamma^2+2\gamma+6)-150+24}$

Inside the bracket becomes zero:

$\boxed{-150+24}$ → $\boxed{-126}$

The point of this question is that γ was the root. I hope you got it, and do well on your test.