Question

Hello friends, please help me . This question is from trigonometric ratios of Optional Mathematics. This is of *Prove that :-* Part. :-
Prove that :- sinA . cosA . cotA = 1 - sin^2A​

Answer 1

Answer:

Step-by-step explanation:

Prove that :- sinA . cosA . cotA = 1 - sin^2A​

We know that

cotA = cosA/sinA

replace the value of cotA

then

sinA . cosA . cosA/sinA and we find becase sinA is devided by sinA

$cos^{2}$A

$cos^{2}$A = 1- $sin^{2}$A

Answer